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151320140435 = 530264028087
BaseRepresentation
bin1000110011101101100…
…0100001101010010011
3112110120202112121002202
42030323120201222103
54434400423443220
6153303203433415
713634565654122
oct2147330415223
9473522477082
10151320140435
11591a1302202
12253b098586b
1311366c19749
147476c35ab9
153e0994c275
hex233b621a93

151320140435 has 4 divisors (see below), whose sum is σ = 181584168528. Its totient is φ = 121056112344.

The previous prime is 151320140429. The next prime is 151320140441. The reversal of 151320140435 is 534041023151.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (151320140429) and next prime (151320140441).

It is a cyclic number.

It is not a de Polignac number, because 151320140435 - 214 = 151320124051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 151320140398 and 151320140407.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15132014039 + ... + 15132014048.

It is an arithmetic number, because the mean of its divisors is an integer number (45396042132).

Almost surely, 2151320140435 is an apocalyptic number.

151320140435 is a deficient number, since it is larger than the sum of its proper divisors (30264028093).

151320140435 is an equidigital number, since it uses as much as digits as its factorization.

151320140435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30264028092.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 151320140435 its reverse (534041023151), we get a palindrome (685361163586).

The spelling of 151320140435 in words is "one hundred fifty-one billion, three hundred twenty million, one hundred forty thousand, four hundred thirty-five".

Divisors: 1 5 30264028087 151320140435