1513343156051 has 4 divisors (see below), whose sum is σ = 1516854393504. Its totient is φ = 1509831918600.

The previous prime is 1513343156047. The next prime is 1513343156107. The reversal of 1513343156051 is 1506513433151.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1513343156051 - 2² = 1513343156047 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1513343155996 and 1513343156014.

It is not an unprimeable number, because it can be changed into a prime (1513343156021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1755618080 + ... + 1755618941.

It is an arithmetic number, because the mean of its divisors is an integer number (379213598376).

Almost surely, 2^{1513343156051} is an apocalyptic number.

1513343156051 is a deficient number, since it is larger than the sum of its proper divisors (3511237453).

1513343156051 is an equidigital number, since it uses as much as digits as its factorization.

1513343156051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3511237452.

The product of its (nonzero) digits is 81000, while the sum is 38.

The spelling of 1513343156051 in words is "one trillion, five hundred thirteen billion, three hundred forty-three million, one hundred fifty-six thousand, fifty-one".