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1513405134047 = 14389105177923
BaseRepresentation
bin10110000001011101111…
…110011011010011011111
312100200100210202111121202
4112001131332123103133
5144243423203242142
63115125420150115
7214224406250012
oct26013576332337
95320323674552
101513405134047
1153391681aa74
1220538439833b
13ac9377066a1
145336bb35379
1529579176032
hex1605df9b4df

1513405134047 has 4 divisors (see below), whose sum is σ = 1513510326360. Its totient is φ = 1513299941736.

The previous prime is 1513405134023. The next prime is 1513405134061. The reversal of 1513405134047 is 7404315043151.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1513405134047 - 238 = 1238527227103 is a prime.

It is a super-3 number, since 3×15134051340473 (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1513405134047.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1513405134097) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52574573 + ... + 52603350.

It is an arithmetic number, because the mean of its divisors is an integer number (378377581590).

Almost surely, 21513405134047 is an apocalyptic number.

1513405134047 is a deficient number, since it is larger than the sum of its proper divisors (105192313).

1513405134047 is a wasteful number, since it uses less digits than its factorization.

1513405134047 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105192312.

The product of its (nonzero) digits is 100800, while the sum is 38.

The spelling of 1513405134047 in words is "one trillion, five hundred thirteen billion, four hundred five million, one hundred thirty-four thousand, forty-seven".

Divisors: 1 14389 105177923 1513405134047