Base | Representation |
---|---|
bin | 11100001100001000… |
… | …11001110100000101 |
3 | 1110001201200011210021 |
4 | 32012010121310011 |
5 | 221443324000031 |
6 | 10541430255141 |
7 | 1044016414141 |
oct | 160604316405 |
9 | 43051604707 |
10 | 15134203141 |
11 | 6466954902 |
12 | 2b244b74b1 |
13 | 15725a69b5 |
14 | a37d9a221 |
15 | 5d89c3511 |
hex | 386119d05 |
15134203141 has 2 divisors, whose sum is σ = 15134203142. Its totient is φ = 15134203140.
The previous prime is 15134203121. The next prime is 15134203211. The reversal of 15134203141 is 14130243151.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15101952100 + 32251041 = 122890^2 + 5679^2 .
It is a cyclic number.
It is not a de Polignac number, because 15134203141 - 25 = 15134203109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15134203111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7567101570 + 7567101571.
It is an arithmetic number, because the mean of its divisors is an integer number (7567101571).
Almost surely, 215134203141 is an apocalyptic number.
It is an amenable number.
15134203141 is a deficient number, since it is larger than the sum of its proper divisors (1).
15134203141 is an equidigital number, since it uses as much as digits as its factorization.
15134203141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 15134203141 its reverse (14130243151), we get a palindrome (29264446292).
The spelling of 15134203141 in words is "fifteen billion, one hundred thirty-four million, two hundred three thousand, one hundred forty-one".
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