15135251040113 has 4 divisors (see below), whose sum is σ = 15504403504548. Its totient is φ = 14766098575680.

The previous prime is 15135251040103. The next prime is 15135251040157. The reversal of 15135251040113 is 31104015253151.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2147537840704 + 12987713199409 = 1465448^2 + 3603847^2 .

It is a cyclic number.

It is not a de Polignac number, because 15135251040113 - 2⁴⁰ = 14035739412337 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 15135251040113.

It is not an unprimeable number, because it can be changed into a prime (15135251040103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 184576232156 + ... + 184576232237.

It is an arithmetic number, because the mean of its divisors is an integer number (3876100876137).

Almost surely, 2^{15135251040113} is an apocalyptic number.

It is an amenable number.

15135251040113 is a deficient number, since it is larger than the sum of its proper divisors (369152464435).

15135251040113 is an equidigital number, since it uses as much as digits as its factorization.

15135251040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 369152464434.

The product of its (nonzero) digits is 9000, while the sum is 32.

Adding to 15135251040113 its reverse (31104015253151), we get a palindrome (46239266293264).

The spelling of 15135251040113 in words is "fifteen trillion, one hundred thirty-five billion, two hundred fifty-one million, forty thousand, one hundred thirteen".