Base | Representation |
---|---|
bin | 1000110011111111001… |
… | …1100111001000100001 |
3 | 112110202221011210221101 |
4 | 2030333303213020201 |
5 | 4440023423141401 |
6 | 153314414154401 |
7 | 13636456511305 |
oct | 2147763471041 |
9 | 473687153841 |
10 | 151394349601 |
11 | 5922a1886a0 |
12 | 254117b2a01 |
13 | 113794000b1 |
14 | 7482a31d05 |
15 | 3e1120a101 |
hex | 233fce7221 |
151394349601 has 4 divisors (see below), whose sum is σ = 165157472304. Its totient is φ = 137631226900.
The previous prime is 151394349599. The next prime is 151394349629. The reversal of 151394349601 is 106943493151.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 151394349601 - 21 = 151394349599 is a prime.
It is a super-2 number, since 2×1513943496012 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (151394343601) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6881561335 + ... + 6881561356.
It is an arithmetic number, because the mean of its divisors is an integer number (41289368076).
Almost surely, 2151394349601 is an apocalyptic number.
151394349601 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
151394349601 is a deficient number, since it is larger than the sum of its proper divisors (13763122703).
151394349601 is a wasteful number, since it uses less digits than its factorization.
151394349601 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13763122702.
The product of its (nonzero) digits is 349920, while the sum is 46.
The spelling of 151394349601 in words is "one hundred fifty-one billion, three hundred ninety-four million, three hundred forty-nine thousand, six hundred one".
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