Base | Representation |
---|---|
bin | 1000110100000000100… |
… | …1010000100001000011 |
3 | 112110210022212002221011 |
4 | 2031000021100201003 |
5 | 4440031401233011 |
6 | 153315135541351 |
7 | 13636555654156 |
oct | 2150011204103 |
9 | 473708762834 |
10 | 151400024131 |
11 | 59232403a94 |
12 | 2541368a857 |
13 | 1137a638bc5 |
14 | 74836abc9d |
15 | 3e1197b621 |
hex | 2340250843 |
151400024131 has 2 divisors, whose sum is σ = 151400024132. Its totient is φ = 151400024130.
The previous prime is 151400024117. The next prime is 151400024143. The reversal of 151400024131 is 131420004151.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 151400024131 - 27 = 151400024003 is a prime.
It is a super-2 number, since 2×1514000241312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (151400084131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75700012065 + 75700012066.
It is an arithmetic number, because the mean of its divisors is an integer number (75700012066).
Almost surely, 2151400024131 is an apocalyptic number.
151400024131 is a deficient number, since it is larger than the sum of its proper divisors (1).
151400024131 is an equidigital number, since it uses as much as digits as its factorization.
151400024131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 151400024131 its reverse (131420004151), we get a palindrome (282820028282).
The spelling of 151400024131 in words is "one hundred fifty-one billion, four hundred million, twenty-four thousand, one hundred thirty-one".
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