15140040763 has 2 divisors, whose sum is σ = 15140040764. Its totient is φ = 15140040762.

The previous prime is 15140040749. The next prime is 15140040833. The reversal of 15140040763 is 36704004151.

15140040763 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 15140040763 - 2¹³ = 15140032571 is a prime.

It is a super-3 number, since 3×15140040763³ (a number of 32 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (15140040263) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7570020381 + 7570020382.

It is an arithmetic number, because the mean of its divisors is an integer number (7570020382).

Almost surely, 2^15140040763 is an apocalyptic number.

15140040763 is a deficient number, since it is larger than the sum of its proper divisors (1).

15140040763 is an equidigital number, since it uses as much as digits as its factorization.

15140040763 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 31.

The spelling of 15140040763 in words is "fifteen billion, one hundred forty million, forty thousand, seven hundred sixty-three".