15140113111 has 2 divisors, whose sum is σ = 15140113112. Its totient is φ = 15140113110.

The previous prime is 15140113069. The next prime is 15140113123. The reversal of 15140113111 is 11131104151.

It is a strong prime.

It is an emirp because it is prime and its reverse (11131104151) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15140113111 - 2²⁷ = 15005895383 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15140113141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7570056555 + 7570056556.

It is an arithmetic number, because the mean of its divisors is an integer number (7570056556).

Almost surely, 2^15140113111 is an apocalyptic number.

15140113111 is a deficient number, since it is larger than the sum of its proper divisors (1).

15140113111 is an equidigital number, since it uses as much as digits as its factorization.

15140113111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 19.

Adding to 15140113111 its reverse (11131104151), we get a palindrome (26271217262).

The spelling of 15140113111 in words is "fifteen billion, one hundred forty million, one hundred thirteen thousand, one hundred eleven".