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15140244103 = 61248200723
BaseRepresentation
bin11100001100110110…
…11100101010000111
31110002011001002102121
432012123130222013
5222001400302403
610542203550411
71044121644235
oct160633345207
943064032377
1015140244103
11646a300536
122b2652b407
13157391052a
14a38acd955
155d92b83bd
hex3866dca87

15140244103 has 4 divisors (see below), whose sum is σ = 15388444888. Its totient is φ = 14892043320.

The previous prime is 15140244089. The next prime is 15140244121. The reversal of 15140244103 is 30144204151.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30144204151 = 132122819231.

It is a cyclic number.

It is not a de Polignac number, because 15140244103 - 25 = 15140244071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15140244503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124100301 + ... + 124100422.

It is an arithmetic number, because the mean of its divisors is an integer number (3847111222).

Almost surely, 215140244103 is an apocalyptic number.

15140244103 is a deficient number, since it is larger than the sum of its proper divisors (248200785).

15140244103 is an equidigital number, since it uses as much as digits as its factorization.

15140244103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 248200784.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 15140244103 its reverse (30144204151), we get a palindrome (45284448254).

The spelling of 15140244103 in words is "fifteen billion, one hundred forty million, two hundred forty-four thousand, one hundred three".

Divisors: 1 61 248200723 15140244103