Base | Representation |
---|---|
bin | 10110000010001011001… |
… | …010011000100001101001 |
3 | 12100202022122021102202022 |
4 | 112002023022120201221 |
5 | 144302001242234423 |
6 | 3115332541114225 |
7 | 214252243131353 |
oct | 26021312304151 |
9 | 5322278242668 |
10 | 1514163243113 |
11 | 534175749594 |
12 | 205556258975 |
13 | aca287b0131 |
14 | 534006b80d3 |
15 | 295c09c5dc8 |
hex | 1608b298869 |
1514163243113 has 2 divisors, whose sum is σ = 1514163243114. Its totient is φ = 1514163243112.
The previous prime is 1514163243107. The next prime is 1514163243127. The reversal of 1514163243113 is 3113423614151.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 869662558249 + 644500684864 = 932557^2 + 802808^2 .
It is a cyclic number.
It is not a de Polignac number, because 1514163243113 - 24 = 1514163243097 is a prime.
It is not a weakly prime, because it can be changed into another prime (1514163243013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 757081621556 + 757081621557.
It is an arithmetic number, because the mean of its divisors is an integer number (757081621557).
Almost surely, 21514163243113 is an apocalyptic number.
It is an amenable number.
1514163243113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1514163243113 is an equidigital number, since it uses as much as digits as its factorization.
1514163243113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 25920, while the sum is 35.
Adding to 1514163243113 its reverse (3113423614151), we get a palindrome (4627586857264).
It can be divided in two parts, 151416324 and 3113, that added together give a cube (151419437 = 5333).
The spelling of 1514163243113 in words is "one trillion, five hundred fourteen billion, one hundred sixty-three million, two hundred forty-three thousand, one hundred thirteen".
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