Base | Representation |
---|---|
bin | 1000110100000101100… |
… | …1101110111000100011 |
3 | 112110211210112220001221 |
4 | 2031001121232320203 |
5 | 4440102301320120 |
6 | 153321212035511 |
7 | 13640233166233 |
oct | 2150131567043 |
9 | 473753486057 |
10 | 151421120035 |
11 | 59243302719 |
12 | 2541a762b97 |
13 | 11381b140a3 |
14 | 74863ddcc3 |
15 | 3e137470aa |
hex | 234166ee23 |
151421120035 has 4 divisors (see below), whose sum is σ = 181705344048. Its totient is φ = 121136896024.
The previous prime is 151421120021. The next prime is 151421120063. The reversal of 151421120035 is 530021124151.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 151421120035 - 27 = 151421119907 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 151421119991 and 151421120009.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15142111999 + ... + 15142112008.
It is an arithmetic number, because the mean of its divisors is an integer number (45426336012).
Almost surely, 2151421120035 is an apocalyptic number.
151421120035 is a deficient number, since it is larger than the sum of its proper divisors (30284224013).
151421120035 is an equidigital number, since it uses as much as digits as its factorization.
151421120035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30284224012.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 151421120035 its reverse (530021124151), we get a palindrome (681442244186).
The spelling of 151421120035 in words is "one hundred fifty-one billion, four hundred twenty-one million, one hundred twenty thousand, thirty-five".
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