Base | Representation |
---|---|
bin | 1101110001100010111110… |
… | …0100101110001010110101 |
3 | 1222121211111211112010112211 |
4 | 3130120233210232022311 |
5 | 3441113124311404031 |
6 | 52113241020413421 |
7 | 3122115400055602 |
oct | 334305744561265 |
9 | 58554454463484 |
10 | 15144852841141 |
11 | 4909994670031 |
12 | 18472106a7271 |
13 | 85b1cc2c76ba |
14 | 3a502c8196a9 |
15 | 1b3e4441ebb1 |
hex | dc62f92e2b5 |
15144852841141 has 4 divisors (see below), whose sum is σ = 15145703358912. Its totient is φ = 15144002323372.
The previous prime is 15144852841103. The next prime is 15144852841169. The reversal of 15144852841141 is 14114825844151.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 15144852841141 - 217 = 15144852710069 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15144852841541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425232175 + ... + 425267788.
It is an arithmetic number, because the mean of its divisors is an integer number (3786425839728).
Almost surely, 215144852841141 is an apocalyptic number.
It is an amenable number.
15144852841141 is a deficient number, since it is larger than the sum of its proper divisors (850517771).
15144852841141 is an equidigital number, since it uses as much as digits as its factorization.
15144852841141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 850517770.
The product of its digits is 819200, while the sum is 49.
The spelling of 15144852841141 in words is "fifteen trillion, one hundred forty-four billion, eight hundred fifty-two million, eight hundred forty-one thousand, one hundred forty-one".
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