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151836120000 = 26365441127
BaseRepresentation
bin1000110101101000100…
…0110101001111000000
3112111220201110002000000
42031122020311033000
54441430021320000
6153430315000000
713653432503535
oct2153210651700
9474821402000
10151836120000
11594365932a4
1225515739000
1311419aa7cb6
1474c558ad8c
153e39dc0000
hex235a2353c0

151836120000 has 980 divisors, whose sum is σ = 582819638016. Its totient is φ = 39191040000.

The previous prime is 151836119987. The next prime is 151836120017. The reversal of 151836120000 is 21638151.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 139 ways as a sum of consecutive naturals, for example, 1195559937 + ... + 1195560063.

Almost surely, 2151836120000 is an apocalyptic number.

151836120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 151836120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (291409819008).

151836120000 is an abundant number, since it is smaller than the sum of its proper divisors (430983518016).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

151836120000 is an frugal number, since it uses more digits than its factorization.

151836120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 218 (or 178 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 151836120000 its reverse (21638151), we get a palindrome (151857758151).

The spelling of 151836120000 in words is "one hundred fifty-one billion, eight hundred thirty-six million, one hundred twenty thousand".