Base | Representation |
---|---|
bin | 100010100011111001010000… |
… | …000000111111100110001101 |
3 | 201221012002011201121002001211 |
4 | 202203321100000333212031 |
5 | 124410332440132340323 |
6 | 1255135535522534421 |
7 | 44005440344120554 |
oct | 4243712000774615 |
9 | 657162151532054 |
10 | 152000235043213 |
11 | 44482a35053537 |
12 | 1506a7b7207411 |
13 | 66a7739a06bbb |
14 | 2976bca1b0d9b |
15 | 1288d1cd8970d |
hex | 8a3e5003f98d |
152000235043213 has 4 divisors (see below), whose sum is σ = 152000273695168. Its totient is φ = 152000196391260.
The previous prime is 152000235043177. The next prime is 152000235043259. The reversal of 152000235043213 is 312340532000251.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 152000235043213 - 213 = 152000235035021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (152000235023213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12660981 + ... + 21547642.
It is an arithmetic number, because the mean of its divisors is an integer number (38000068423792).
Almost surely, 2152000235043213 is an apocalyptic number.
It is an amenable number.
152000235043213 is a deficient number, since it is larger than the sum of its proper divisors (38651955).
152000235043213 is an equidigital number, since it uses as much as digits as its factorization.
152000235043213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38651954.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 152000235043213 its reverse (312340532000251), we get a palindrome (464340767043464).
The spelling of 152000235043213 in words is "one hundred fifty-two trillion, two hundred thirty-five million, forty-three thousand, two hundred thirteen".
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