Base | Representation |
---|---|
bin | 1000110110010000000… |
… | …0010001110111101001 |
3 | 112112100020220212200102 |
4 | 2031210000101313221 |
5 | 4442244410301103 |
6 | 153454550515145 |
7 | 13660512464663 |
oct | 2154400216751 |
9 | 475306825612 |
10 | 152001650153 |
11 | 59510a72581 |
12 | 25561065ab5 |
13 | 11445183932 |
14 | 74dd559533 |
15 | 3e496bae88 |
hex | 2364011de9 |
152001650153 has 2 divisors, whose sum is σ = 152001650154. Its totient is φ = 152001650152.
The previous prime is 152001650123. The next prime is 152001650167. The reversal of 152001650153 is 351056100251.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 151981463104 + 20187049 = 389848^2 + 4493^2 .
It is an emirp because it is prime and its reverse (351056100251) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 152001650153 - 214 = 152001633769 is a prime.
It is not a weakly prime, because it can be changed into another prime (152001650123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76000825076 + 76000825077.
It is an arithmetic number, because the mean of its divisors is an integer number (76000825077).
Almost surely, 2152001650153 is an apocalyptic number.
It is an amenable number.
152001650153 is a deficient number, since it is larger than the sum of its proper divisors (1).
152001650153 is an equidigital number, since it uses as much as digits as its factorization.
152001650153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 29.
The spelling of 152001650153 in words is "one hundred fifty-two billion, one million, six hundred fifty thousand, one hundred fifty-three".
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