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152010113 is a prime number
BaseRepresentation
bin10010000111101…
…11110110000001
3101121000220200012
421003313312001
5302403310423
623030034305
73524031113
oct1103676601
9347026605
10152010113
11788954a2
1242aa8995
1325653b18
141628d3b3
15d52a078
hex90f7d81

152010113 has 2 divisors, whose sum is σ = 152010114. Its totient is φ = 152010112.

The previous prime is 152010071. The next prime is 152010139. The reversal of 152010113 is 311010251.

152010113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 146216464 + 5793649 = 12092^2 + 2407^2 .

It is a cyclic number.

It is not a de Polignac number, because 152010113 - 226 = 84901249 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (152010713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76005056 + 76005057.

It is an arithmetic number, because the mean of its divisors is an integer number (76005057).

Almost surely, 2152010113 is an apocalyptic number.

It is an amenable number.

152010113 is a deficient number, since it is larger than the sum of its proper divisors (1).

152010113 is an equidigital number, since it uses as much as digits as its factorization.

152010113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30, while the sum is 14.

The square root of 152010113 is about 12329.2381354243. The cubic root of 152010113 is about 533.6921652476.

Adding to 152010113 its reverse (311010251), we get a palindrome (463020364).

The spelling of 152010113 in words is "one hundred fifty-two million, ten thousand, one hundred thirteen".