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152015542345 = 530403108469
BaseRepresentation
bin1000110110010011010…
…1010001100001001001
3112112101020001200012001
42031210311101201021
54442311434323340
6153500204351001
713661041535002
oct2154465214111
9475336050161
10152015542345
11595188a0a27
1225565845461
1311448008c74
1475013341a9
153e4aa1229a
hex2364d51849

152015542345 has 4 divisors (see below), whose sum is σ = 182418650820. Its totient is φ = 121612433872.

The previous prime is 152015542339. The next prime is 152015542369. The reversal of 152015542345 is 543245510251.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 57617281296 + 94398261049 = 240036^2 + 307243^2 .

It is a cyclic number.

It is not a de Polignac number, because 152015542345 - 211 = 152015540297 is a prime.

It is a super-2 number, since 2×1520155423452 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15201554230 + ... + 15201554239.

It is an arithmetic number, because the mean of its divisors is an integer number (45604662705).

Almost surely, 2152015542345 is an apocalyptic number.

It is an amenable number.

152015542345 is a deficient number, since it is larger than the sum of its proper divisors (30403108475).

152015542345 is an equidigital number, since it uses as much as digits as its factorization.

152015542345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30403108474.

The product of its (nonzero) digits is 120000, while the sum is 37.

It can be divided in two parts, 1520155 and 42345, that added together give a square (1562500 = 12502).

The spelling of 152015542345 in words is "one hundred fifty-two billion, fifteen million, five hundred forty-two thousand, three hundred forty-five".

Divisors: 1 5 30403108469 152015542345