Base | Representation |
---|---|
bin | 100010100100001100101000… |
… | …001001111011011110000111 |
3 | 201221021001212201220222020102 |
4 | 202210030220021323132013 |
5 | 124411203043012232242 |
6 | 1255153300245354315 |
7 | 44010105055015013 |
oct | 4244145011733607 |
9 | 657231781828212 |
10 | 152021041133447 |
11 | 444908415a3032 |
12 | 1507284310899b |
13 | 66a96a43b77b5 |
14 | 2977c01569543 |
15 | 1289639781e32 |
hex | 8a432827b787 |
152021041133447 has 2 divisors, whose sum is σ = 152021041133448. Its totient is φ = 152021041133446.
The previous prime is 152021041133411. The next prime is 152021041133503. The reversal of 152021041133447 is 744331140120251.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 152021041133447 - 236 = 151952321656711 is a prime.
It is a super-2 number, since 2×1520210411334472 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 152021041133447.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152021041133947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76010520566723 + 76010520566724.
It is an arithmetic number, because the mean of its divisors is an integer number (76010520566724).
Almost surely, 2152021041133447 is an apocalyptic number.
152021041133447 is a deficient number, since it is larger than the sum of its proper divisors (1).
152021041133447 is an equidigital number, since it uses as much as digits as its factorization.
152021041133447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 38.
Adding to 152021041133447 its reverse (744331140120251), we get a palindrome (896352181253698).
The spelling of 152021041133447 in words is "one hundred fifty-two trillion, twenty-one billion, forty-one million, one hundred thirty-three thousand, four hundred forty-seven".
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