Base | Representation |
---|---|
bin | 1101110101000000000111… |
… | …0010011010110011001111 |
3 | 1222211111201211102201120102 |
4 | 3131100001302122303033 |
5 | 3443101212320101111 |
6 | 52200415233041315 |
7 | 3126316413350162 |
oct | 335200162326317 |
9 | 58744654381512 |
10 | 15204214222031 |
11 | 49320866120aa |
12 | 18568186b623b |
13 | 86399c656b53 |
14 | 3a7c60551ad9 |
15 | 1b576aa7713b |
hex | dd401c9accf |
15204214222031 has 4 divisors (see below), whose sum is σ = 15204222555864. Its totient is φ = 15204205888200.
The previous prime is 15204214221949. The next prime is 15204214222037. The reversal of 15204214222031 is 13022241240251.
15204214222031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 15204214222031 - 238 = 14929336315087 is a prime.
It is a super-2 number, since 2×152042142220312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 15204214221985 and 15204214222003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15204214222037) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120560 + ... + 5515701.
It is an arithmetic number, because the mean of its divisors is an integer number (3801055638966).
Almost surely, 215204214222031 is an apocalyptic number.
15204214222031 is a deficient number, since it is larger than the sum of its proper divisors (8333833).
15204214222031 is an equidigital number, since it uses as much as digits as its factorization.
15204214222031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8333832.
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 15204214222031 its reverse (13022241240251), we get a palindrome (28226455462282).
The spelling of 15204214222031 in words is "fifteen trillion, two hundred four billion, two hundred fourteen million, two hundred twenty-two thousand, thirty-one".
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