Base | Representation |
---|---|
bin | 11100010100100000… |
… | …01110101011100100 |
3 | 1110020121210011102021 |
4 | 32022100032223210 |
5 | 222114312142012 |
6 | 10552415152524 |
7 | 1045531241110 |
oct | 161220165344 |
9 | 43217704367 |
10 | 15204412132 |
11 | 64a2548968 |
12 | 2b43b15744 |
13 | 1583cb9690 |
14 | a43434740 |
15 | 5dec41007 |
hex | 38a40eae4 |
15204412132 has 96 divisors (see below), whose sum is σ = 33063174144. Its totient is φ = 5957366400.
The previous prime is 15204412087. The next prime is 15204412133. The reversal of 15204412132 is 23121440251.
It is a junction number, because it is equal to n+sod(n) for n = 15204412097 and 15204412106.
It is not an unprimeable number, because it can be changed into a prime (15204412133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 26627407 + ... + 26627977.
It is an arithmetic number, because the mean of its divisors is an integer number (344408064).
Almost surely, 215204412132 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 15204412132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16531587072).
15204412132 is an abundant number, since it is smaller than the sum of its proper divisors (17858762012).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
15204412132 is a wasteful number, since it uses less digits than its factorization.
15204412132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1169 (or 1167 counting only the distinct ones).
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 15204412132 its reverse (23121440251), we get a palindrome (38325852383).
The spelling of 15204412132 in words is "fifteen billion, two hundred four million, four hundred twelve thousand, one hundred thirty-two".
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