Base | Representation |
---|---|
bin | 1000110110100111100… |
… | …0110001001010110111 |
3 | 112112121010122001212201 |
4 | 2031221320301022313 |
5 | 4443000142011003 |
6 | 153512434125331 |
7 | 13663121411422 |
oct | 2155170611267 |
9 | 475533561781 |
10 | 152100344503 |
11 | 59561752058 |
12 | 2558a120847 |
13 | 1145c75b063 |
14 | 750c6ca9b9 |
15 | 3e531b3b1d |
hex | 2369e312b7 |
152100344503 has 2 divisors, whose sum is σ = 152100344504. Its totient is φ = 152100344502.
The previous prime is 152100344393. The next prime is 152100344509. The reversal of 152100344503 is 305443001251.
It is a strong prime.
It is an emirp because it is prime and its reverse (305443001251) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-152100344503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152100344509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76050172251 + 76050172252.
It is an arithmetic number, because the mean of its divisors is an integer number (76050172252).
Almost surely, 2152100344503 is an apocalyptic number.
152100344503 is a deficient number, since it is larger than the sum of its proper divisors (1).
152100344503 is an equidigital number, since it uses as much as digits as its factorization.
152100344503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 152100344503 its reverse (305443001251), we get a palindrome (457543345754).
The spelling of 152100344503 in words is "one hundred fifty-two billion, one hundred million, three hundred forty-four thousand, five hundred three".
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