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152100344503 is a prime number
BaseRepresentation
bin1000110110100111100…
…0110001001010110111
3112112121010122001212201
42031221320301022313
54443000142011003
6153512434125331
713663121411422
oct2155170611267
9475533561781
10152100344503
1159561752058
122558a120847
131145c75b063
14750c6ca9b9
153e531b3b1d
hex2369e312b7

152100344503 has 2 divisors, whose sum is σ = 152100344504. Its totient is φ = 152100344502.

The previous prime is 152100344393. The next prime is 152100344509. The reversal of 152100344503 is 305443001251.

It is a strong prime.

It is an emirp because it is prime and its reverse (305443001251) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152100344503 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152100344509) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76050172251 + 76050172252.

It is an arithmetic number, because the mean of its divisors is an integer number (76050172252).

Almost surely, 2152100344503 is an apocalyptic number.

152100344503 is a deficient number, since it is larger than the sum of its proper divisors (1).

152100344503 is an equidigital number, since it uses as much as digits as its factorization.

152100344503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 152100344503 its reverse (305443001251), we get a palindrome (457543345754).

The spelling of 152100344503 in words is "one hundred fifty-two billion, one hundred million, three hundred forty-four thousand, five hundred three".