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152100456341 is a prime number
BaseRepresentation
bin1000110110100111100…
…1001100011110010101
3112112121010211202021212
42031221321030132111
54443000204100331
6153512440351205
713663122355451
oct2155171143625
9475533752255
10152100456341
1159561819089
122558a175505
131145c799c32
14750c719661
153e531d6d2b
hex2369e4c795

152100456341 has 2 divisors, whose sum is σ = 152100456342. Its totient is φ = 152100456340.

The previous prime is 152100456329. The next prime is 152100456359. The reversal of 152100456341 is 143654001251.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118298163025 + 33802293316 = 343945^2 + 183854^2 .

It is an emirp because it is prime and its reverse (143654001251) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 152100456341 - 210 = 152100455317 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 152100456298 and 152100456307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152100456371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76050228170 + 76050228171.

It is an arithmetic number, because the mean of its divisors is an integer number (76050228171).

Almost surely, 2152100456341 is an apocalyptic number.

It is an amenable number.

152100456341 is a deficient number, since it is larger than the sum of its proper divisors (1).

152100456341 is an equidigital number, since it uses as much as digits as its factorization.

152100456341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 152100456341 its reverse (143654001251), we get a palindrome (295754457592).

The spelling of 152100456341 in words is "one hundred fifty-two billion, one hundred million, four hundred fifty-six thousand, three hundred forty-one".