Base | Representation |
---|---|
bin | 1000110110101100001… |
… | …1110011010100010111 |
3 | 112112122111122101111102 |
4 | 2031223003303110113 |
5 | 4443020210422403 |
6 | 153514415500315 |
7 | 13663450533251 |
oct | 2155303632427 |
9 | 475574571442 |
10 | 152120014103 |
11 | 59571867122 |
12 | 2559482769b |
13 | 11463856c85 |
14 | 751116acd1 |
15 | 3e54c9bb88 |
hex | 236b0f3517 |
152120014103 has 4 divisors (see below), whose sum is σ = 154613784888. Its totient is φ = 149626243320.
The previous prime is 152120014097. The next prime is 152120014117. The reversal of 152120014103 is 301410021251.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301410021251 = 19 ⋅15863685329.
It is a cyclic number.
It is not a de Polignac number, because 152120014103 - 28 = 152120013847 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (152120013103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1246885301 + ... + 1246885422.
It is an arithmetic number, because the mean of its divisors is an integer number (38653446222).
Almost surely, 2152120014103 is an apocalyptic number.
152120014103 is a deficient number, since it is larger than the sum of its proper divisors (2493770785).
152120014103 is an equidigital number, since it uses as much as digits as its factorization.
152120014103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2493770784.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 152120014103 its reverse (301410021251), we get a palindrome (453530035354).
The spelling of 152120014103 in words is "one hundred fifty-two billion, one hundred twenty million, fourteen thousand, one hundred three".
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