Search a number
-
+
152120112577 = 990715354811
BaseRepresentation
bin1000110110101100010…
…0001011010111000001
3112112122111211101120121
42031223010023113001
54443020222100302
6153514421540241
713663451423326
oct2155304132701
9475574741517
10152120112577
1159571924104
1225594874681
131146388ca44
147511194b4d
153e54cbae37
hex236b10b5c1

152120112577 has 4 divisors (see below), whose sum is σ = 152135477296. Its totient is φ = 152104747860.

The previous prime is 152120112569. The next prime is 152120112583. The reversal of 152120112577 is 775211021251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 775211021251 = 3720951649223.

It is a cyclic number.

It is not a de Polignac number, because 152120112577 - 23 = 152120112569 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (152120122577) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7667499 + ... + 7687312.

It is an arithmetic number, because the mean of its divisors is an integer number (38033869324).

Almost surely, 2152120112577 is an apocalyptic number.

It is an amenable number.

152120112577 is a deficient number, since it is larger than the sum of its proper divisors (15364719).

152120112577 is an equidigital number, since it uses as much as digits as its factorization.

152120112577 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15364718.

The product of its (nonzero) digits is 9800, while the sum is 34.

The spelling of 152120112577 in words is "one hundred fifty-two billion, one hundred twenty million, one hundred twelve thousand, five hundred seventy-seven".

Divisors: 1 9907 15354811 152120112577