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15212214284117 is a prime number
BaseRepresentation
bin1101110101011101111010…
…1000001110111101010101
31222212021101100221222122012
43131113132220032331111
53443214103324042432
652204221134114005
73130021564636304
oct335273650167525
958767340858565
1015212214284117
114935511422164
12185828b94b905
13864675bbc2b6
143a83bcc3443b
151b5a88085cb2
hexdd5dea0ef55

15212214284117 has 2 divisors, whose sum is σ = 15212214284118. Its totient is φ = 15212214284116.

The previous prime is 15212214284053. The next prime is 15212214284129. The reversal of 15212214284117 is 71148241221251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10209360553681 + 5002853730436 = 3195209^2 + 2236706^2 .

It is a cyclic number.

It is not a de Polignac number, because 15212214284117 - 26 = 15212214284053 is a prime.

It is a super-2 number, since 2×152122142841172 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15212214184117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7606107142058 + 7606107142059.

It is an arithmetic number, because the mean of its divisors is an integer number (7606107142059).

Almost surely, 215212214284117 is an apocalyptic number.

It is an amenable number.

15212214284117 is a deficient number, since it is larger than the sum of its proper divisors (1).

15212214284117 is an equidigital number, since it uses as much as digits as its factorization.

15212214284117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 71680, while the sum is 41.

The spelling of 15212214284117 in words is "fifteen trillion, two hundred twelve billion, two hundred fourteen million, two hundred eighty-four thousand, one hundred seventeen".