Search a number
-
+
15212220031 is a prime number
BaseRepresentation
bin11100010101011100…
…00000111001111111
31110021011110211211201
432022232000321333
5222123312020111
610553254400331
71045654510501
oct161256007177
943234424751
1015212220031
1164a69a1078
122b466600a7
1315857c1538
14a444a7d71
155e07846c1
hex38ab80e7f

15212220031 has 2 divisors, whose sum is σ = 15212220032. Its totient is φ = 15212220030.

The previous prime is 15212219933. The next prime is 15212220043. The reversal of 15212220031 is 13002221251.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 15212220031 - 225 = 15178665599 is a prime.

It is a super-2 number, since 2×152122200312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 15212219990 and 15212220008.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15212220061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7606110015 + 7606110016.

It is an arithmetic number, because the mean of its divisors is an integer number (7606110016).

Almost surely, 215212220031 is an apocalyptic number.

15212220031 is a deficient number, since it is larger than the sum of its proper divisors (1).

15212220031 is an equidigital number, since it uses as much as digits as its factorization.

15212220031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 15212220031 its reverse (13002221251), we get a palindrome (28214441282).

The spelling of 15212220031 in words is "fifteen billion, two hundred twelve million, two hundred twenty thousand, thirty-one".