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15213011014343 is a prime number
BaseRepresentation
bin1101110101100000111000…
…0111100001001011000111
31222212100102220011002001002
43131120032013201023013
53443222221304424333
652204432154523515
73130050411014042
oct335301607411307
958770386132032
1015213011014343
11493589012a39a
12185847273659b
13864771c98abc
143a845698bc59
151b5ad2eb40e8
hexdd60e1e12c7

15213011014343 has 2 divisors, whose sum is σ = 15213011014344. Its totient is φ = 15213011014342.

The previous prime is 15213011014321. The next prime is 15213011014373. The reversal of 15213011014343 is 34341011031251.

15213011014343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15213011014343 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15213011014373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7606505507171 + 7606505507172.

It is an arithmetic number, because the mean of its divisors is an integer number (7606505507172).

Almost surely, 215213011014343 is an apocalyptic number.

15213011014343 is a deficient number, since it is larger than the sum of its proper divisors (1).

15213011014343 is an equidigital number, since it uses as much as digits as its factorization.

15213011014343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 15213011014343 its reverse (34341011031251), we get a palindrome (49554022045594).

The spelling of 15213011014343 in words is "fifteen trillion, two hundred thirteen billion, eleven million, fourteen thousand, three hundred forty-three".