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15213408950849 is a prime number
BaseRepresentation
bin1101110101100010010111…
…0101100001101001000001
31222212101110121221100022012
43131120211311201221001
53443224030142411344
652204535452022305
73130063312302554
oct335304565415101
958771417840265
1015213408950849
114935a74815a3a
121858563a61995
138648065670a5
143a849377669b
151b5b07dbb29e
hexdd625d61a41

15213408950849 has 2 divisors, whose sum is σ = 15213408950850. Its totient is φ = 15213408950848.

The previous prime is 15213408950797. The next prime is 15213408950851. The reversal of 15213408950849 is 94805980431251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9748132840000 + 5465276110849 = 3122200^2 + 2337793^2 .

It is a cyclic number.

It is not a de Polignac number, because 15213408950849 - 228 = 15213140515393 is a prime.

It is a super-3 number, since 3×152134089508493 (a number of 41 digits) contains 333 as substring.

Together with 15213408950851, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (15213408950249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7606704475424 + 7606704475425.

It is an arithmetic number, because the mean of its divisors is an integer number (7606704475425).

Almost surely, 215213408950849 is an apocalyptic number.

It is an amenable number.

15213408950849 is a deficient number, since it is larger than the sum of its proper divisors (1).

15213408950849 is an equidigital number, since it uses as much as digits as its factorization.

15213408950849 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12441600, while the sum is 59.

The spelling of 15213408950849 in words is "fifteen trillion, two hundred thirteen billion, four hundred eight million, nine hundred fifty thousand, eight hundred forty-nine".