Base | Representation |
---|---|
bin | 1101110101100010010111… |
… | …0101101000110010100011 |
3 | 1222212101110121222211110201 |
4 | 3131120211311220302203 |
5 | 3443224030144331011 |
6 | 52204535452410031 |
7 | 3130063312454125 |
oct | 335304565506243 |
9 | 58771417884421 |
10 | 15213408980131 |
11 | 4935a74835a3a |
12 | 1858563a76917 |
13 | 86480657750b |
14 | 3a8493783215 |
15 | 1b5b07dc4cc1 |
hex | dd625d68ca3 |
15213408980131 has 2 divisors, whose sum is σ = 15213408980132. Its totient is φ = 15213408980130.
The previous prime is 15213408980089. The next prime is 15213408980153. The reversal of 15213408980131 is 13108980431251.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 15213408980131 - 29 = 15213408979619 is a prime.
It is a super-3 number, since 3×152134089801313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (15213408980831) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7606704490065 + 7606704490066.
It is an arithmetic number, because the mean of its divisors is an integer number (7606704490066).
Almost surely, 215213408980131 is an apocalyptic number.
15213408980131 is a deficient number, since it is larger than the sum of its proper divisors (1).
15213408980131 is an equidigital number, since it uses as much as digits as its factorization.
15213408980131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 207360, while the sum is 46.
The spelling of 15213408980131 in words is "fifteen trillion, two hundred thirteen billion, four hundred eight million, nine hundred eighty thousand, one hundred thirty-one".
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