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15213408980842 = 210373851499907
BaseRepresentation
bin1101110101100010010111…
…0101101000111101101010
31222212101110121222212110001
43131120211311220331222
53443224030144341332
652204535452413214
73130063312456162
oct335304565507552
958771417885401
1015213408980842
114935a74836526
121858563a7720a
13864806577937
143a84937835a2
151b5b07dc50e7
hexdd625d68f6a

15213408980842 has 8 divisors (see below), whose sum is σ = 23041667971296. Its totient is φ = 7532852990412.

The previous prime is 15213408980831. The next prime is 15213408980849. The reversal of 15213408980842 is 24808980431251.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×152134089808423 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (15213408980849) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36925749748 + ... + 36925750159.

It is an arithmetic number, because the mean of its divisors is an integer number (2880208496412).

Almost surely, 215213408980842 is an apocalyptic number.

15213408980842 is a deficient number, since it is larger than the sum of its proper divisors (7828258990454).

15213408980842 is a wasteful number, since it uses less digits than its factorization.

15213408980842 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 73851500012.

The product of its (nonzero) digits is 4423680, while the sum is 55.

The spelling of 15213408980842 in words is "fifteen trillion, two hundred thirteen billion, four hundred eight million, nine hundred eighty thousand, eight hundred forty-two".

Divisors: 1 2 103 206 73851499907 147702999814 7606704490421 15213408980842