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15213408980849 is a prime number
BaseRepresentation
bin1101110101100010010111…
…0101101000111101110001
31222212101110121222212110022
43131120211311220331301
53443224030144341344
652204535452413225
73130063312456202
oct335304565507561
958771417885408
1015213408980849
114935a74836532
121858563a77215
13864806577941
143a84937835a9
151b5b07dc50ee
hexdd625d68f71

15213408980849 has 2 divisors, whose sum is σ = 15213408980850. Its totient is φ = 15213408980848.

The previous prime is 15213408980831. The next prime is 15213408981073. The reversal of 15213408980849 is 94808980431251.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13215638750224 + 1997770230625 = 3635332^2 + 1413425^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15213408980849 is a prime.

It is a super-3 number, since 3×152134089808493 (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 15213408980791 and 15213408980800.

It is not a weakly prime, because it can be changed into another prime (15213408950849) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7606704490424 + 7606704490425.

It is an arithmetic number, because the mean of its divisors is an integer number (7606704490425).

Almost surely, 215213408980849 is an apocalyptic number.

It is an amenable number.

15213408980849 is a deficient number, since it is larger than the sum of its proper divisors (1).

15213408980849 is an equidigital number, since it uses as much as digits as its factorization.

15213408980849 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19906560, while the sum is 62.

The spelling of 15213408980849 in words is "fifteen trillion, two hundred thirteen billion, four hundred eight million, nine hundred eighty thousand, eight hundred forty-nine".