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152136503 is a prime number
BaseRepresentation
bin10010001000101…
…10101100110111
3101121021100001022
421010112230313
5302421332003
623032451355
73525065441
oct1104265467
9347240038
10152136503
1178971452
1242b49b5b
13256994cc
14162c3491
15d552738
hex9116b37

152136503 has 2 divisors, whose sum is σ = 152136504. Its totient is φ = 152136502.

The previous prime is 152136493. The next prime is 152136557. The reversal of 152136503 is 305631251.

152136503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152136503 is a prime.

It is a super-3 number, since 3×1521365033 (a number of 26 digits) contains 333 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152136583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76068251 + 76068252.

It is an arithmetic number, because the mean of its divisors is an integer number (76068252).

Almost surely, 2152136503 is an apocalyptic number.

152136503 is a deficient number, since it is larger than the sum of its proper divisors (1).

152136503 is an equidigital number, since it uses as much as digits as its factorization.

152136503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 26.

The square root of 152136503 is about 12334.3626912784. The cubic root of 152136503 is about 533.8400384498.

Adding to 152136503 its reverse (305631251), we get a palindrome (457767754).

The spelling of 152136503 in words is "one hundred fifty-two million, one hundred thirty-six thousand, five hundred three".