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152144552324437 is a prime number
BaseRepresentation
bin100010100101111111101001…
…111111101110110101010101
3201221200212200110000120021121
4202211333221333232311111
5124420214020343340222
61255330124211043541
744022036560556601
oct4245775177566525
9657625613016247
10152144552324437
1144529162428992
12150927728a05b1
1366b8228b5916a
14297db9ad44501
15128c967b055c7
hex8a5fe9feed55

152144552324437 has 2 divisors, whose sum is σ = 152144552324438. Its totient is φ = 152144552324436.

The previous prime is 152144552324423. The next prime is 152144552324441. The reversal of 152144552324437 is 734423255441251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141026288951601 + 11118263372836 = 11875449^2 + 3334406^2 .

It is a cyclic number.

It is not a de Polignac number, because 152144552324437 - 247 = 11407063969109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152144552324137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76072276162218 + 76072276162219.

It is an arithmetic number, because the mean of its divisors is an integer number (76072276162219).

Almost surely, 2152144552324437 is an apocalyptic number.

It is an amenable number.

152144552324437 is a deficient number, since it is larger than the sum of its proper divisors (1).

152144552324437 is an equidigital number, since it uses as much as digits as its factorization.

152144552324437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 16128000, while the sum is 52.

The spelling of 152144552324437 in words is "one hundred fifty-two trillion, one hundred forty-four billion, five hundred fifty-two million, three hundred twenty-four thousand, four hundred thirty-seven".