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152145333173 is a prime number
BaseRepresentation
bin1000110110110010010…
…0011000101110110101
3112112201021021201201202
42031230210120232311
54443043201130143
6153521122302245
713664205664631
oct2155444305665
9475637251652
10152145333173
115958508a779
12255a11b7985
1311468b80482
14751467bdc1
153e570edab8
hex236c918bb5

152145333173 has 2 divisors, whose sum is σ = 152145333174. Its totient is φ = 152145333172.

The previous prime is 152145333091. The next prime is 152145333181. The reversal of 152145333173 is 371333541251.

152145333173 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90996945649 + 61148387524 = 301657^2 + 247282^2 .

It is an emirp because it is prime and its reverse (371333541251) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 152145333173 - 210 = 152145332149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152145339173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76072666586 + 76072666587.

It is an arithmetic number, because the mean of its divisors is an integer number (76072666587).

Almost surely, 2152145333173 is an apocalyptic number.

It is an amenable number.

152145333173 is a deficient number, since it is larger than the sum of its proper divisors (1).

152145333173 is an equidigital number, since it uses as much as digits as its factorization.

152145333173 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 113400, while the sum is 38.

The spelling of 152145333173 in words is "one hundred fifty-two billion, one hundred forty-five million, three hundred thirty-three thousand, one hundred seventy-three".