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152240120031 = 350746706677
BaseRepresentation
bin1000110111001000110…
…1111110000011011111
3112112221212122101212010
42031302031332003133
54443241432320111
6153534350042303
713666436445306
oct2156215760337
9475855571763
10152240120031
115962364051a
1225608aa9393
13114826ba17c
1475230b343d
153e605c3aa6
hex237237e0df

152240120031 has 4 divisors (see below), whose sum is σ = 202986826712. Its totient is φ = 101493413352.

The previous prime is 152240120029. The next prime is 152240120069. The reversal of 152240120031 is 130021042251.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 152240120031 - 21 = 152240120029 is a prime.

It is a super-2 number, since 2×1522401200312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (152240220031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25373353336 + ... + 25373353341.

It is an arithmetic number, because the mean of its divisors is an integer number (50746706678).

Almost surely, 2152240120031 is an apocalyptic number.

152240120031 is a deficient number, since it is larger than the sum of its proper divisors (50746706681).

152240120031 is an equidigital number, since it uses as much as digits as its factorization.

152240120031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50746706680.

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 152240120031 its reverse (130021042251), we get a palindrome (282261162282).

The spelling of 152240120031 in words is "one hundred fifty-two billion, two hundred forty million, one hundred twenty thousand, thirty-one".

Divisors: 1 3 50746706677 152240120031