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1523234434121 is a prime number
BaseRepresentation
bin10110001010100111110…
…110001110110001001001
312101121201211022200110122
4112022213312032301021
5144424041003342441
63123433024153025
7215023112026361
oct26124766166111
95347654280418
101523234434121
11538000144664
12207268168775
13b0842c2808a
1453a213419a1
152995206634b
hex162a7d8ec49

1523234434121 has 2 divisors, whose sum is σ = 1523234434122. Its totient is φ = 1523234434120.

The previous prime is 1523234434097. The next prime is 1523234434123. The reversal of 1523234434121 is 1214344323251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1280663408896 + 242571025225 = 1131664^2 + 492515^2 .

It is a cyclic number.

It is not a de Polignac number, because 1523234434121 - 214 = 1523234417737 is a prime.

Together with 1523234434123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1523234434123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 761617217060 + 761617217061.

It is an arithmetic number, because the mean of its divisors is an integer number (761617217061).

Almost surely, 21523234434121 is an apocalyptic number.

It is an amenable number.

1523234434121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1523234434121 is an equidigital number, since it uses as much as digits as its factorization.

1523234434121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69120, while the sum is 35.

Adding to 1523234434121 its reverse (1214344323251), we get a palindrome (2737578757372).

The spelling of 1523234434121 in words is "one trillion, five hundred twenty-three billion, two hundred thirty-four million, four hundred thirty-four thousand, one hundred twenty-one".