1523641403441 has 2 divisors, whose sum is σ = 1523641403442. Its totient is φ = 1523641403440.

The previous prime is 1523641403429. The next prime is 1523641403443. The reversal of 1523641403441 is 1443041463251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1522992937216 + 648466225 = 1234096^2 + 25465^2 .

It is a cyclic number.

It is not a de Polignac number, because 1523641403441 - 2¹⁴ = 1523641387057 is a prime.

Together with 1523641403443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1523641403395 and 1523641403404.

It is not a weakly prime, because it can be changed into another prime (1523641403443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 761820701720 + 761820701721.

It is an arithmetic number, because the mean of its divisors is an integer number (761820701721).

Almost surely, 2^{1523641403441} is an apocalyptic number.

It is an amenable number.

1523641403441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1523641403441 is an equidigital number, since it uses as much as digits as its factorization.

1523641403441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 38.

Adding to 1523641403441 its reverse (1443041463251), we get a palindrome (2966682866692).

The spelling of 1523641403441 in words is "one trillion, five hundred twenty-three billion, six hundred forty-one million, four hundred three thousand, four hundred forty-one".