Base | Representation |
---|---|
bin | 100010101001111000001110… |
… | …011101101101011100111111 |
3 | 201222122101121011002202120011 |
4 | 202221320032131231130333 |
5 | 124434102123221311411 |
6 | 1300052504324204051 |
7 | 44050235602540012 |
oct | 4251701635553477 |
9 | 658571534082504 |
10 | 152411452135231 |
11 | 44621374410113 |
12 | 1511643ab39627 |
13 | 670745222c7a3 |
14 | 298ca79dd5379 |
15 | 1294889405c21 |
hex | 8a9e0e76d73f |
152411452135231 has 2 divisors, whose sum is σ = 152411452135232. Its totient is φ = 152411452135230.
The previous prime is 152411452135207. The next prime is 152411452135309. The reversal of 152411452135231 is 132531254114251.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 152411452135231 - 227 = 152411317917503 is a prime.
It is a super-2 number, since 2×1524114521352312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152411452135031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76205726067615 + 76205726067616.
It is an arithmetic number, because the mean of its divisors is an integer number (76205726067616).
Almost surely, 2152411452135231 is an apocalyptic number.
152411452135231 is a deficient number, since it is larger than the sum of its proper divisors (1).
152411452135231 is an equidigital number, since it uses as much as digits as its factorization.
152411452135231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 144000, while the sum is 40.
The spelling of 152411452135231 in words is "one hundred fifty-two trillion, four hundred eleven billion, four hundred fifty-two million, one hundred thirty-five thousand, two hundred thirty-one".
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