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152503162113 = 350834387371
BaseRepresentation
bin1000111000000111100…
…1011001010100000001
3112120122012121022202110
42032001321121110001
54444311302141423
6154020424005533
714006112326661
oct2160171312401
9476565538673
10152503162113
1159749071975
12256810008a9
13114c5047c83
147549dc61a1
153e78732193
hex2381e59501

152503162113 has 4 divisors (see below), whose sum is σ = 203337549488. Its totient is φ = 101668774740.

The previous prime is 152503162081. The next prime is 152503162121. The reversal of 152503162113 is 311261305251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 152503162113 - 25 = 152503162081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (152503162193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25417193683 + ... + 25417193688.

It is an arithmetic number, because the mean of its divisors is an integer number (50834387372).

Almost surely, 2152503162113 is an apocalyptic number.

It is an amenable number.

152503162113 is a deficient number, since it is larger than the sum of its proper divisors (50834387375).

152503162113 is an equidigital number, since it uses as much as digits as its factorization.

152503162113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50834387374.

The product of its (nonzero) digits is 5400, while the sum is 30.

Adding to 152503162113 its reverse (311261305251), we get a palindrome (463764467364).

The spelling of 152503162113 in words is "one hundred fifty-two billion, five hundred three million, one hundred sixty-two thousand, one hundred thirteen".

Divisors: 1 3 50834387371 152503162113