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152509221433 is a prime number
BaseRepresentation
bin1000111000001001000…
…0100000101000111001
3112120122122000011120201
42032002100200220321
54444314330041213
6154021201522201
714006214664432
oct2160220405071
9476578004521
10152509221433
1159751530378
1225683043361
13114c6389c7a
14754ab22489
153e7902c6dd
hex2382420a39

152509221433 has 2 divisors, whose sum is σ = 152509221434. Its totient is φ = 152509221432.

The previous prime is 152509221427. The next prime is 152509221499. The reversal of 152509221433 is 334122905251.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 148975156729 + 3534064704 = 385973^2 + 59448^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152509221433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 152509221392 and 152509221401.

It is not a weakly prime, because it can be changed into another prime (152509221133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76254610716 + 76254610717.

It is an arithmetic number, because the mean of its divisors is an integer number (76254610717).

Almost surely, 2152509221433 is an apocalyptic number.

It is an amenable number.

152509221433 is a deficient number, since it is larger than the sum of its proper divisors (1).

152509221433 is an equidigital number, since it uses as much as digits as its factorization.

152509221433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 37.

The spelling of 152509221433 in words is "one hundred fifty-two billion, five hundred nine million, two hundred twenty-one thousand, four hundred thirty-three".