Base | Representation |
---|---|
bin | 10110001100011001100… |
… | …000011001101001010011 |
3 | 12101210122201110020002012 |
4 | 112030121200121221103 |
5 | 144441442134023011 |
6 | 3124350143213135 |
7 | 215121265162331 |
oct | 26143140315123 |
9 | 5353581406065 |
10 | 1525141314131 |
11 | 538899569856 |
12 | 2076ba8a71ab |
13 | b0a87cca346 |
14 | 53b626bab51 |
15 | 29a14682a8b |
hex | 16319819a53 |
1525141314131 has 2 divisors, whose sum is σ = 1525141314132. Its totient is φ = 1525141314130.
The previous prime is 1525141314119. The next prime is 1525141314143. The reversal of 1525141314131 is 1314131415251.
It is a balanced prime because it is at equal distance from previous prime (1525141314119) and next prime (1525141314143).
It is a cyclic number.
It is not a de Polignac number, because 1525141314131 - 226 = 1525074205267 is a prime.
It is a super-2 number, since 2×15251413141312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1525141316131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 762570657065 + 762570657066.
It is an arithmetic number, because the mean of its divisors is an integer number (762570657066).
Almost surely, 21525141314131 is an apocalyptic number.
1525141314131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1525141314131 is an equidigital number, since it uses as much as digits as its factorization.
1525141314131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7200, while the sum is 32.
Adding to 1525141314131 its reverse (1314131415251), we get a palindrome (2839272729382).
The spelling of 1525141314131 in words is "one trillion, five hundred twenty-five billion, one hundred forty-one million, three hundred fourteen thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •