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152522410081 is a prime number
BaseRepresentation
bin1000111000001100001…
…0110100100001100001
3112120200112211020000011
42032003002310201201
54444331214110311
6154022352324521
714006435044336
oct2160302644141
9476615736004
10152522410081
1159758a19188
1225687543741
13114c9026cc2
14754c79698d
153e7a285321
hex23830b4861

152522410081 has 2 divisors, whose sum is σ = 152522410082. Its totient is φ = 152522410080.

The previous prime is 152522410039. The next prime is 152522410091. The reversal of 152522410081 is 180014225251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 146903558400 + 5618851681 = 383280^2 + 74959^2 .

It is a cyclic number.

It is not a de Polignac number, because 152522410081 - 27 = 152522409953 is a prime.

It is a super-2 number, since 2×1525224100812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (152522410091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76261205040 + 76261205041.

It is an arithmetic number, because the mean of its divisors is an integer number (76261205041).

Almost surely, 2152522410081 is an apocalyptic number.

It is an amenable number.

152522410081 is a deficient number, since it is larger than the sum of its proper divisors (1).

152522410081 is an equidigital number, since it uses as much as digits as its factorization.

152522410081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6400, while the sum is 31.

The spelling of 152522410081 in words is "one hundred fifty-two billion, five hundred twenty-two million, four hundred ten thousand, eighty-one".