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152535441050341 is a prime number
BaseRepresentation
bin100010101011101011101100…
…110001111000101011100101
3202000002020122011010020220021
4202223223230301320223211
5124443120040402102331
61300225451513035141
744062215266120356
oct4253535461705345
9660066564106807
10152535441050341
1144669a0a978198
12151364826b5ab1
136716051956c4b
142994a7d007d2d
151297be4692211
hex8abaecc78ae5

152535441050341 has 2 divisors, whose sum is σ = 152535441050342. Its totient is φ = 152535441050340.

The previous prime is 152535441050249. The next prime is 152535441050359. The reversal of 152535441050341 is 143050144535251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94085150062500 + 58450290987841 = 9699750^2 + 7645279^2 .

It is a cyclic number.

It is not a de Polignac number, because 152535441050341 - 211 = 152535441048293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152535441054341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76267720525170 + 76267720525171.

It is an arithmetic number, because the mean of its divisors is an integer number (76267720525171).

Almost surely, 2152535441050341 is an apocalyptic number.

It is an amenable number.

152535441050341 is a deficient number, since it is larger than the sum of its proper divisors (1).

152535441050341 is an equidigital number, since it uses as much as digits as its factorization.

152535441050341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720000, while the sum is 43.

Adding to 152535441050341 its reverse (143050144535251), we get a palindrome (295585585585592).

The spelling of 152535441050341 in words is "one hundred fifty-two trillion, five hundred thirty-five billion, four hundred forty-one million, fifty thousand, three hundred forty-one".