Base | Representation |
---|---|
bin | 11100011010100011… |
… | …01100111110111001 |
3 | 1110101011012220022100 |
4 | 32031101230332321 |
5 | 222220303130131 |
6 | 11001430214013 |
7 | 1050015315534 |
oct | 161521547671 |
9 | 43334186270 |
10 | 15255130041 |
11 | 6519139a98 |
12 | 2b58ab4309 |
13 | 1591666788 |
14 | a4a077a1b |
15 | 5e440d7e6 |
hex | 38d46cfb9 |
15255130041 has 6 divisors (see below), whose sum is σ = 22035187850. Its totient is φ = 10170086688.
The previous prime is 15255130031. The next prime is 15255130049. The reversal of 15255130041 is 14003155251.
15255130041 is a `hidden beast` number, since 1 + 525 + 5 + 130 + 0 + 4 + 1 = 666.
It can be written as a sum of positive squares in only one way, i.e., 14504589225 + 750540816 = 120435^2 + 27396^2 .
It is not a de Polignac number, because 15255130041 - 27 = 15255129913 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 15255129987 and 15255130014.
It is not an unprimeable number, because it can be changed into a prime (15255130049) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 847507216 + ... + 847507233.
Almost surely, 215255130041 is an apocalyptic number.
It is an amenable number.
15255130041 is a deficient number, since it is larger than the sum of its proper divisors (6780057809).
15255130041 is a wasteful number, since it uses less digits than its factorization.
15255130041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1695014455 (or 1695014452 counting only the distinct ones).
The product of its (nonzero) digits is 3000, while the sum is 27.
Adding to 15255130041 its reverse (14003155251), we get a palindrome (29258285292).
The spelling of 15255130041 in words is "fifteen billion, two hundred fifty-five million, one hundred thirty thousand, forty-one".
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