Base | Representation |
---|---|
bin | 1000111000101000010… |
… | …0110110111010000111 |
3 | 112120222202210221200112 |
4 | 2032022010312322013 |
5 | 10000101414302042 |
6 | 154042205103235 |
7 | 14012366601452 |
oct | 2161204667207 |
9 | 476882727615 |
10 | 152640384647 |
11 | 59809577223 |
12 | 256bab57b1b |
13 | 115175c203a |
14 | 7560306499 |
15 | 3e857da982 |
hex | 238a136e87 |
152640384647 has 2 divisors, whose sum is σ = 152640384648. Its totient is φ = 152640384646.
The previous prime is 152640384623. The next prime is 152640384667. The reversal of 152640384647 is 746483046251.
It is a strong prime.
It is an emirp because it is prime and its reverse (746483046251) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-152640384647 is a prime.
It is a super-2 number, since 2×1526403846472 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 152640384595 and 152640384604.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152640384667) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76320192323 + 76320192324.
It is an arithmetic number, because the mean of its divisors is an integer number (76320192324).
Almost surely, 2152640384647 is an apocalyptic number.
152640384647 is a deficient number, since it is larger than the sum of its proper divisors (1).
152640384647 is an equidigital number, since it uses as much as digits as its factorization.
152640384647 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3870720, while the sum is 50.
The spelling of 152640384647 in words is "one hundred fifty-two billion, six hundred forty million, three hundred eighty-four thousand, six hundred forty-seven".
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