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1530104540413 is a prime number
BaseRepresentation
bin10110010001000001010…
…101100110110011111101
312102021110121122020120211
4112101001111212303331
5200032123230243123
63130530442312421
7215355262666651
oct26210125466375
95367417566524
101530104540413
1153aa0613a159
12208664ab8711
13b1399351a27
14540b3928a61
1529c0527340d
hex16441566cfd

1530104540413 has 2 divisors, whose sum is σ = 1530104540414. Its totient is φ = 1530104540412.

The previous prime is 1530104540407. The next prime is 1530104540431. The reversal of 1530104540413 is 3140454010351.

Together with next prime (1530104540431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1449526905369 + 80577635044 = 1203963^2 + 283862^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1530104540413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1530104540443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 765052270206 + 765052270207.

It is an arithmetic number, because the mean of its divisors is an integer number (765052270207).

Almost surely, 21530104540413 is an apocalyptic number.

It is an amenable number.

1530104540413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1530104540413 is an equidigital number, since it uses as much as digits as its factorization.

1530104540413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1530104540413 its reverse (3140454010351), we get a palindrome (4670558550764).

The spelling of 1530104540413 in words is "one trillion, five hundred thirty billion, one hundred four million, five hundred forty thousand, four hundred thirteen".