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153014215000147 is a prime number
BaseRepresentation
bin100010110010101001100101…
…111011100100000001010011
3202001210000102201202220012121
4202302221211323210001103
5130023441103020001042
61301233432052235111
744141624614416544
oct4262514573440123
9661700381686177
10153014215000147
1144833a67327a46
12151b321b00ba97
13674c2423b46b7
1429adcdb1944cb
1512a53b6ac5367
hex8b2a65ee4053

153014215000147 has 2 divisors, whose sum is σ = 153014215000148. Its totient is φ = 153014215000146.

The previous prime is 153014215000061. The next prime is 153014215000181. The reversal of 153014215000147 is 741000512410351.

It is an a-pointer prime, because the next prime (153014215000181) can be obtained adding 153014215000147 to its sum of digits (34).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 153014215000147 - 215 = 153014214967379 is a prime.

It is a super-2 number, since 2×1530142150001472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (153014215000447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76507107500073 + 76507107500074.

It is an arithmetic number, because the mean of its divisors is an integer number (76507107500074).

Almost surely, 2153014215000147 is an apocalyptic number.

153014215000147 is a deficient number, since it is larger than the sum of its proper divisors (1).

153014215000147 is an equidigital number, since it uses as much as digits as its factorization.

153014215000147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16800, while the sum is 34.

Adding to 153014215000147 its reverse (741000512410351), we get a palindrome (894014727410498).

The spelling of 153014215000147 in words is "one hundred fifty-three trillion, fourteen billion, two hundred fifteen million, one hundred forty-seven", and thus it is an aban number.