Base | Representation |
---|---|
bin | 10110010001001101000… |
… | …100001100110011010111 |
3 | 12102021222022212212111221 |
4 | 112101031010030303113 |
5 | 200033024113212043 |
6 | 3131002151511211 |
7 | 215363202314542 |
oct | 26211504146327 |
9 | 5367868785457 |
10 | 1530301304023 |
11 | 53aaa7211608 |
12 | 2086ba988507 |
13 | b13cb044bbb |
14 | 540d1b07859 |
15 | 29c1768d8ed |
hex | 1644d10ccd7 |
1530301304023 has 2 divisors, whose sum is σ = 1530301304024. Its totient is φ = 1530301304022.
The previous prime is 1530301303919. The next prime is 1530301304071. The reversal of 1530301304023 is 3204031030351.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1530301304023 - 217 = 1530301172951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1530301305023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 765150652011 + 765150652012.
It is an arithmetic number, because the mean of its divisors is an integer number (765150652012).
Almost surely, 21530301304023 is an apocalyptic number.
1530301304023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1530301304023 is an equidigital number, since it uses as much as digits as its factorization.
1530301304023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 1530301304023 its reverse (3204031030351), we get a palindrome (4734332334374).
The spelling of 1530301304023 in words is "one trillion, five hundred thirty billion, three hundred one million, three hundred four thousand, twenty-three".
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