Base | Representation |
---|---|
bin | 100010110010111010101101… |
… | …111101110100011011110100 |
3 | 202001211202220020211102122201 |
4 | 202302322231331310123310 |
5 | 130024241232433423104 |
6 | 1301250112452034244 |
7 | 44143145400414331 |
oct | 4262725575643364 |
9 | 661752806742581 |
10 | 153032603420404 |
11 | 44840843096284 |
12 | 151b68b1302984 |
13 | 6750bb2c30946 |
14 | 29b0b6340d988 |
15 | 12a5ae11060a4 |
hex | 8b2eadf746f4 |
153032603420404 has 24 divisors (see below), whose sum is σ = 275316370414848. Its totient is φ = 74392346301600.
The previous prime is 153032603420401. The next prime is 153032603420423. The reversal of 153032603420404 is 404024306230351.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153032603420401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2695346479 + ... + 2695403254.
It is an arithmetic number, because the mean of its divisors is an integer number (11471515433952).
Almost surely, 2153032603420404 is an apocalyptic number.
It is an amenable number.
153032603420404 is a deficient number, since it is larger than the sum of its proper divisors (122283766994444).
153032603420404 is a wasteful number, since it uses less digits than its factorization.
153032603420404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5390749935 (or 5390749933 counting only the distinct ones).
The product of its (nonzero) digits is 207360, while the sum is 37.
Adding to 153032603420404 its reverse (404024306230351), we get a palindrome (557056909650755).
The spelling of 153032603420404 in words is "one hundred fifty-three trillion, thirty-two billion, six hundred three million, four hundred twenty thousand, four hundred four".
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